二甲基 - 艾蕊尔 海伦托
type: channel
link: https://www.ariels.xyz/author/1/
description: 艾蕊尔 海伦托
items: Why is artificial intelligence important?
items: What is Artificial Intelligence?
items: Handsome 静态资源加速
items: 提问的智慧
items: EVE Online：二步验证取代邮箱验证
items: 导数不等式证明之变换主元和函数同构
items: 高中英语作文速查
items: 宝塔纯净版
items: 一个针对 Mirai Http 组件的 PHP 类
items: 一些奇怪的数学题

Why is artificial intelligence important?
type: item
date: 2022-09-07T09:51:00+00:00
description: The content is provided by Jeri's Class, AI EFE. It is reorganize by Ariel Xiong mailto:ArielHeleneto@outlook.com.TextAI automates repetitive learning and discovery through data. But AI is different from hardware-driven, robotic automation. Instead of automating manual tasks, AI performs frequent, high-volume, computerized tasks reliably and without fatigue. For this type of automation, human inquiry is still essential to set up the system and ask the right questions.AI adds intelligence to existing products. In most cases, AI will not be sold as an individual application. Rather, products you already use will be improved with AI capabilities, much like Siri was added as a feature to a new generation of Apple products. Automation, conversational platforms, bots and smart machines can be combined with large amounts of data to improve many technologies at home and in the workplace, from security intelligence to investment analysis.AI adapts through progressive learning algorithms to let the data do the programming. AI finds structure regularities in data so that the algorithm requires a skill: The algorithm can teach itself how to play chess, it can teach itself what product to recommend next online. And the models adapt when given new data. Back propagation1 is an AI technique that allows the model to adjust, through training and added data, when the first answer is not quite right.AI analyzes more and deeper data using neural networks that have many hidden layers. Building a fraud detection2 system with five hidden was almost impossible a few years ago.All that has changed with incredible computer power and big data. You need lots of data to train deep learning models because they learn directly from the data. The more data you can feed them, the more accurate they become.AI achieves incredible accuracy through deep neural networks--which was previously impossible. For example, your interactions with Alexa, Google Search and Google Photos are all based on deep learn…

What is Artificial Intelligence?
type: item
date: 2022-09-07T09:35:00+00:00
description: What is Artificial Intelligence?The content is provided by Jeri's Class, AI EFE. It is reorganize by Ariel Xiong mailto:ArielHeleneto@outlook.com.TextArtificial Intelligence (AI), sometimes called machine intelligence, is intelligence demonstrated by machines, in contrast to the natural intelligence displayed by humans and other animals. In computer science AI research is defined as the study of “intelligent agent”: any device that perceives its environment and takes actions that maximize its chance of successfully achieving its goals. Colloquially, the term “artificial intelligence” is applied when a machine mimics “cognitive” functions that human associate with other human minds, such as “learning” and “problem solving”.For years, it was thought that computer would never be more powerful than the human brain, but as development has accelerated in modern times, this has proven to be not the case.AI as a concept refers to computing hardware being able to essentially think for itself, and make decisions based on the data it is being fed. AI systems are often hugely complex and powerful, with the ability to process unfathomable depths of information in an extremely quick time in order to come to an effective conclusion.Thanks to detailed algorithms, AI systems are now able to perform mammoth computing tasks much faster and more efficiently than human minds, helping making big strides in research and development areas around the world.Some of the most notable real-world application of AI are IBM’s Watson, which is being used to power research in a huge range of fields, with Microsoft’s Azure Machine Learning and TensorFlow also making headlines around the world.But AI-powered smart assistants are becoming a common presence on mobile devices too, with the likes of Siri, Cortana and Alexa all being welcomed into many people’s lives.There seems to limit to the applications of AI technologies, and perhaps the most exciting aspect of the ecosystem is that there’s no telling…

Handsome 静态资源加速
type: item
date: 2022-02-01T15:07:00+00:00
description: 为了提高各位使用 Handsome 主题的用户的加载速度，博主将 Handsome 主题的静态文件全部处理后存放在阿里云 CDN 上，未设置防盗链。供各位博主使用。[...]

提问的智慧
type: item
date: 2021-11-16T00:56:13+00:00
description: # 提问的智慧 [![PRs Welcome](https://img.shields.io/badge/PRs-welcome-brightgreen.svg?style=flat-square)](https://github.com/ryanhanwu/How-To-Ask-Questions-The-Smart-Way/pulls) **How To Ask Questions The Smart Way** Copyright © 2001,2006,2014 Eric S. Raymond, Rick Moen 本指南英文版版权为 Eric S. Raymond, Rick Moen 所有。 原文网址：[http://www.catb.org/~esr/faqs/smart-questions.html](http://www.catb.org/~esr/faqs/smart-questions.html) Copyleft 2001 by D.H.Grand(nOBODY/Ginux), 2010 by Gasolin, 2015 by Ryan Wu 本中文指南是基于原文 3.10 版以及 2010 年由 [Gasolin](https://github.com/gasolin) 所翻译版本的最新翻译； 协助指出翻译问题，**请[发 issue](https://github.com/ryanhanwu/How-To-Ask-Questions-The-Smart-Way/issues/new)，或直接[发 pull request](https://github.com/ryanhanwu/How-To-Ask-Questions-The-Smart-Way/compare) 给我。** 本文另有[繁體中文版](README.md)。 ## [原文版本历史](history.md) ## 目录 * [声明](#声明) * [简介](#简介) * [在提问之前](#在提问之前) * [当你提问时](#当你提问时) * [慎选提问的论坛](#慎选提问的论坛) * [Stack Overflow](#stack-overflow) * [网站和 IRC 论坛](#网站和-irc-论坛) * [第二步，使用项目邮件列表](#第二步使用项目邮件列表) * [使用有意义且描述明确的标题](#使用有意义且描述明确的标题) * [使问题容易回复](#使问题容易回复) * [使用清晰、正确、精准且合乎语法的语句](#使用清晰、正确、精准且合乎语法的语句) * [使用易于读取且标准的文件格式发送问题](#使用易于读取且标准的文件格式发送问题) * [精确地描述问题并言之有物](#精确地描述问题并言之有物) * [话不在多而在精](#话不在多而在精) * [别动辄声称找到 Bug](#别动辄声称找到-bug) * [低声下气不能代替你的功课](#低声下气不能代替你的功课) * [描述问题症状而非你的猜测](#描述问题症状而非你的猜测) * [按发生时间先后列出问题症状](#按发生时间先后列出问题症状) * [描述目标而不是过程](#描述目标而不是过程) * [别要求使用私人电邮回复](#别要求使用私人电邮回复) * [清楚明确的表达你的问题以及需求](#清楚明确的表达你的问题以及需求) * [询问有关代码的问题时](#询问有关代码的问题时) * [别把自己家庭作业的问题贴上来](#别把自己家庭作业的问题贴上来) * [去掉无意义的提问句](#去掉无意义的提问句) * [即使你很急也不要在标题写紧急](#即使你很急也不要在标题写紧急) * [礼多人不怪，而且有时还很有帮助](#礼多人不怪而且有时还很有帮助) * [问题解决后，加个简短的补充说明](#问题解决后加个简短的补充说明) * [如何解读答案](#如何解读答案) * [RTFM 和 STFW：如何知道你已完全搞砸了](#rtfm-和-stfw如何知道你已完全搞砸了) * [如果还是搞不懂](#如果还是搞不懂) * [处理无礼的回应](#处理无礼的回应) * [如何避免扮演失败者](#如何避免扮演失败者) * [不该问的问题](#不该问的问题) * [好问题与蠢问题](#好问题与蠢问题) * [如果得不到回答](#如果得不到回答) * [如何更好地回答问题](#如何更好地回答问题) * [相关资源](#相关资源) * [鸣谢](#鸣谢) ## 声明 许多项目在他们的使用协助/说明网页中链接了本指南，这么做很好，我们也鼓励大家都这么做。但如果你是负责管理这个项目网页的人，请在超链接附近的显著位置上注明： **本指南不提供此项目的实际支持服务！** 我们已经深刻领教到少了上述声明所…

EVE Online：二步验证取代邮箱验证
type: item
date: 2021-10-24T09:27:00+00:00
description: 众所周知， EVE Online 是一款来自冰岛的游戏，出于某些不可名状的原因，国内玩家时常收不到来自游戏的验证邮件无法登陆账户。本文简要概述了设置 虚拟 MFA （一种离线验证方案）取代原始邮件验证的方法。[...]

导数不等式证明之变换主元和函数同构
type: item
date: 2021-09-21T08:53:28+00:00
description: 题目已知 $f(x)=e^{ax-1}+x\ln x$。当 $a=1$ 时，试求 $y=f(x)$ 在 $(1,f(1))$ 的切线方程。试证明 $\forall a \in\mathbb{R},x \in\mathbb{R^*},f(x)\geq ax^2$。

高中英语作文速查
type: item
date: 2021-07-10T15:43:00+00:00
description: 本文整理了高中英语作文常见的模板句型等。[...]

宝塔纯净版
type: item
date: 2021-07-04T01:59:00+00:00
description: 宝塔纯净版介绍基于 BT 官方剥离了所有与 BT 官方的通信、上报、下发；所有功能与原版一致，不会有任何异常，如有任何问题请参考宝塔官方解决方案；提升为企业会员，软件商店中的所有「运行环境」、「免费插件」、「宝塔插件」、「专业版插件」、「企业版插件」；部分「第三方应用」安装可能会失败。宝塔 7.4.5 版本 [推荐/稳定版本]CentOS 安装命令根据系统执行框内命令开始安装（大约 2 分钟完成面板安装）升级后可能需要重启面板。yum install -y wget && wget -O install.sh http://download.hostcli.com/install/install_6.0.sh && sh install.sh升级纯净版官方 及其他破解版（7.4.5 至 7.5.2 版本之间所有版本均可），一键升级为 7.4.5 纯净版。wget -O update7.sh http://download.hostcli.com/install/update7.sh && bash update7.sh宝塔纯净版 7.4.5 版本说明一键安装，基于 宝塔7.4.5正式版 ，非7.4.5版本的请先使用 官方升级到7.4.5版本；本命令行升级安装，不影响网站数据，不宕机，不修改任何网站数据，无缝切换，升级后重启面板即可；2020-11-08 经站长测试，该净化版本已支持Debian系统；理论上宝塔支持的系统，纯净版都支持，但还是建议先测试；2020-11-13 某主机论坛站长反馈 /Api/SetupCount?type=会返回 ok 。接口只是适应/模拟官网，以便成功通过企业插件的安装校验，服务端并未做任何记录。宝塔纯净版 7.5.1版本（内测，不推荐正式建站使用）升级安装安装宝塔官方7.5.1版本 （不一定 7.5.1 ，差几个小版本都没影响）使用纯净版覆盖安装，代码如下。wget -O update7.sh http://www.hostcli.com/install/update7.sh && bash update7.sh宝塔纯净版 7.5.1 版本说明默认为企业版，到期时间：2099-01-29。包含 企业版所有插件 和 专业版所有插件 ，包含部分常用第三方插件。修复"升级通道"修复"修复功能"完全去掉上报功能，接口调用注释同步官网最新版本修改登录接口,不验证，不记录， 默认返回绑定号码 18988889999默认关闭活动推荐及在线客服功能7.5.1 纯净版 恢复到 7.4.5 纯净版wget -O update7.sh http://download.hostcli.com/install/update7.sh && bash update7.sh任意版本还原到官方最新版curl http://download.bt.cn/install/update6.sh|bash

一个针对 Mirai Http 组件的 PHP 类
type: item
date: 2021-06-13T07:58:00+00:00
description: 这个类可以轻松使用，用于与 Mirai 后端交互。[...]

一些奇怪的数学题
type: item
date: 2021-06-12T10:03:00+00:00
description: 导数例一已知函数 $f(x)=x \sin x+2 \cos x+a x^{2}$，记 $f(x)$ 的导函数为 $f'(x)$，并定义$$ \max \left\{a, b\right\}=\begin{cases}a &a\gt b\\b &a\leq b\end{cases} $$当 $a=0$ 时，求证： $f(x)$ 在 $[-\pi,\pi]$ 有且只有两个零点。$\forall x_{1}, x_{2} \in\left[0, \frac{\pi}{2}\right], \quad x_{1} \neq x_{2}, \cfrac{f\left(x_{1}\right)-f\left(x_{2}\right)}{x_{1}-x_{2}}\lt\max \left\{f^{\prime}\left(x_{1}\right), f^{\prime}\left(x_{2}\right)\right\}$，试求 $a$ 的范围。[collapse status="false" title="解析"]第一问考察零点存在性定理及其推论，所以直接代入求导即可。第二问本意为考察拉格朗日中值定理1，但是可以使用定积分的集合意义绕过。[/collapse][collapse status="false" title="第一问参考答案"]当$a=0$时，$f'(x)=x\cos(x)-\sin(x)$，$f''(x)=-x\sin(x)$，$\because x \in [-\pi,\pi]$$\therefore f''(x)\leq 0$$\therefore f'(x)\swarrow$所以$f(x)$的增减性如下表。$x$$(-\infty,0)$$(0,+\infty)$$f'(x)$$+$$-$$f(x)$$\nearrow$$\searrow$$\because f(0)=2 \gt0 ,f(\pi)=f(-\pi)=-2\lt0$$\therefore \exists x_0 \in (-\pi,0),x_1 \in (0,\pi),s.t. f(x_0)=f(x_1)=0\square$[scode type="blue"]QED 是拉丁词组「Quod Erat Demonstrandum」（这就是所要证明的）的缩写，代表证明完毕。现在的 QED 符号通常是$\square$或者$\blacksquare$，也可书写为「Q.E.D」。[/scode][/collapse][collapse status="false" title="第二问参考答案（定积分做法）"]$f(x)=x\sin x+2\cos x+ax^2$$f'(x)=x\cos x-\sin x+2ax$$f''(x)=-x\sin x+2a$不妨设$x_1\gt x_2$。当$f'(x)\searrow$时。$\because f(x_1)-f(x_2)=\int^{x_2}_{x_1}f'(x)\rm{dx}\lt f'(x_2)\cdot (x_1-x_2)$$\therefore \cfrac{f(x_1)-f(x_2)}{x_1-x_2}\lt f'(x_1)$$\because f'(x)\searrow,x_1\gt x_2$$\therefore \max\left\{f'(x_1),f'(x_2)\right\}=f'(x_1)$$\therefore\cfrac{f\left(x_{1}\right)-f\left(x_{2}\right)}{x_{1}-x_{2}}\lt\max \left\{f^{\prime}\left(x_{1}\right), f^{\prime}\left(x_{2}\right)\right\}\square$此时，$f''(x)=-x\sin x+2a\lt0\Rightarrow a\in(-\infty,0]$。当$f'(x)$先增后减时。令$f'(x_1)=f'(x_2)$。此时$f(x_1)-f(x_2)=\int^{x_2}_{x_1}f'(x)\rm{dx}\geq f'(x_2)\cdot (x_1-x_2)$，与题设矛盾，故舍去。当$f'(x)\nearrow$时。$\because f(x_1)-f(x_2)=\int^{x_2}_{x_1}f'(x)\rm{dx}\lt f'(x_1)\cdot (x_1-x_2)$$\therefore \cfrac{f(x_1)-f(x_2)}{x_1-x_2}\lt f'(x_1)$$\because f'(x)\nearrow,x_1\gt x_2$$\therefore \max\left\{f'(x_1),f'(x_2)\right\…